szabist imc larkana
posted by basit shah .
ten bricks each 6.0cm thick and mass of 1.5kg, lie on a table, how much work is required to stack them one on the top of another?
A. 40j
B. 88j
C. 45j
D. 0j
E. None of these

szabist imc larkana 
Damon
original height of center of mass = 3 cm
final height of center of mass = 5^6 = 30cm
change in height of GC = 303 = 27 cm=.27m
work = m g h = 15 * 9.8 * .27 = 39.69 or 40 J so A
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