If a tank is standing up i.e 1.200 dia x 1.100 high with 650 kg inside, How much water pressure to lift it Cheers

To calculate the water pressure required to lift a tank, we need to consider the weight of the water inside the tank as well as the dimensions of the tank. Here are the steps to calculate the water pressure:

1. Calculate the volume of water inside the tank.
- The formula for calculating the volume of a cylinder is V = π * r^2 * h, where V is the volume, π is a mathematical constant (approximately equal to 3.14159), r is the radius of the cylinder, and h is the height of the cylinder.
- Given the diameter of the tank (1.200 m), we can calculate the radius by dividing it by 2. So, the radius (r) would be 1.200 / 2 = 0.600 m.
- The height of the tank is given as 1.100 m.
- Substituting the values into the formula, V = 3.14159 * (0.600)^2 * 1.100 = 1.2387 cubic meters.

2. Calculate the weight (mass) of water inside the tank.
- The weight of an object can be calculated using the formula W = m * g, where W is the weight, m is the mass, and g is the acceleration due to gravity (approximately equal to 9.8 m/s^2).
- Given the mass of water inside the tank as 650 kg, the weight would be W = 650 kg * 9.8 m/s^2 = 6370 N.

3. Calculate the pressure exerted by the water.
- Pressure is defined as force per unit area. In this case, the force is the weight of the water, and the area is the base area of the tank, which is a circle.
- The formula for pressure is P = F / A, where P is the pressure, F is the force, and A is the area.
- The base area of the tank can be calculated using the formula A = π * r^2, where A is the area, and r is the radius of the circle.
- Substituting the values, A = 3.14159 * (0.600)^2 = 1.131 square meters.
- Now, we can calculate the pressure P = 6370 N / 1.131 m^2 ≈ 5634.88 Pa (Pascal).

Therefore, the water pressure required to lift the tank with 650 kg of water inside is approximately 5634.88 Pascal.