Math
posted by Robert
The formula h=48t16t^2 gives the height, h, in feet, of an object projected into the air after t seconds. If an object is propelled upward, at what time(s) will it reach a height of 32 feet above the ground?

Henry
h = 48t  16t^2 = 32 Ft.
Divide both sides by 16:
3t  t^2 = 2,
t^2 + 3t  2 = 0.
Solve using the Quadratic Eq and get:
t = 1s, and t = 2s.
Respond to this Question
Similar Questions

MATH
The height h in feet of an object after t seconds is given by the function h=16t^2+60t+9.... How long will it take the object to hit the ground? 
Algebra
THe function h(t)=16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the time … 
Algebra
THe function h(t)=16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the time … 
Algebra II
If an object is propelled upward from a height of 16 ft at an initial velocity of 80 feet per sec, the its height after t seconds is given by the equation h=16tÂ²+80t+16, where h is in feet. after how many seconds will the object … 
math
An object that is falling or vertically projected into the air has it height, in feet, above the ground given by the formula below, where s is the height in feet, Vo is the original velocity of the object, in feet per second, t is … 
algebra
Please help me solve this: If an object is projected upward with an initial velocity of 112 feet per second from a height h of 128 feet, then its height t seconds after it is projected is defined by the equation h=16t^2 + 112t + 128. … 
Math
If an object is propelled upward from ground level with initial velocity of 55 feet per second, it's height h in feet t seconds later is given by the equation H=16t^2+55t. after how many seconds does the object hit ground? 
Math
an object is thrown upward from a height of 70 feet. t second after it is released, the object is h=16t^2+40t+70 feet above the ground. how many seconds does it take until the object hits the ground? 
Math
In physics, one learns that the height of an object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula h(t)=−16t^2+v0t+h0 feet where t is the amount of … 
Maths
object thrown upward from an initial height of h0 feet with an initial velocity of v0 (in feet per second) is given by the formula h(t)=−16t^2+v0t+h0 feet where t is the amount of time in seconds after the ball was thrown. Also, …