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/b2-4ac; b=3, a=-1, c=-2
What would the solution be?
b^2-4ac=9-8=1
X1=(-b-sqrt(1))/2a=(-3-1)/(-2)=2
X2=(-b+sqrt(1))/2a=(-3+1)/(-2)=1
To find the solution to the quadratic equation represented by the expression b^2 - 4ac, where b = 3, a = -1, and c = -2, we need to substitute these values into the expression and simplify it.
Substituting the given values, we have:
b^2 - 4ac = 3^2 - 4(-1)(-2)
Now, let's evaluate the expression step by step:
b^2 - 4ac = 9 - 4(-1)(-2)
Next, we simplify the double negatives:
b^2 - 4ac = 9 - 4(2)
Next, we perform the multiplication:
b^2 - 4ac = 9 - 8
Finally, we subtract:
b^2 - 4ac = 1
Therefore, the solution to the quadratic expression represented by b^2 - 4ac when b = 3, a = -1, and c = -2 is 1.