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Pre cal

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)a function f is defined as f(x) = 3*2^x
describe the end behavior of f, please describe in detail how you got the answer and explain your abbreviations.

  • Pre cal -

    F(x) = 3*2^x.

    F(-2) = 3 * 2^-2 = 0.75.

    F(-1) = 3 * 2^-1 = 1.50.

    F(0) = 3 * 2^0 = 3.0.

    F(1) = 3 * 2^1 = 6.0

    So when x is increased by 1, F(x) doubles. This is normal behavior for
    base 2 numerals.

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