Pre Cal

posted by .

simplify the quotient: [(x+1)^3(4x-9)-(16x+9)(x+1)^2]/[(x-6)(x+1)^3]

  • Pre Cal -

    = (x+1)^2[(x+1)(4x-9) - (16x+9)]/[(x-6)(x+1)^2]
    expand the square bracket and factor the result...
    = (x+1)^(4x+3)(x-6)/(x-6)(x+1)^2]
    = (4x+3)/(x+1) , x ≠ -1, 6

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Algebra

    There are two solutions to | 16x - 5 | = 3. The greatest solution is ___. Since the expression, 16x - 5, can be either positive or negative, solve for both. 16x - 5 = 3 16x = 8 x = .5 -(16x - 5) = 3 -16x + 5 = 3 -16x = -2 x = 1/8 You …
  2. PRE-CAL

    SIMPLIFY 55/SQUARE ROOT OF 20 -3
  3. Pre-cal

    let P(x)=2x^4-x^3+13^2-8x-24. Use synethetic division to show that x+1 is a factor of P(x) Answer:2x^3-3x^2+16x-24 Then find all real and imaginary roots of P(x)=0.
  4. Pre-Cal

    Simplify e^3ln2-1
  5. Pre Cal

    simplify the expression 2sin^2 t + cos^2 t-2
  6. Pre Cal

    simplify the quotient: [x(5x+1)-3(x^2+1)]/ [(x-1)^2]
  7. pre cal

    (y^2)^-4y^8 simplify
  8. Pre-Calculus

    Help please If f(x)=8x and g(x)=2x+1 find (fog)(x) 16x^2+8x 16x+1 16x+8 10x+1
  9. pre cal

    Can you simplify (2x^-4 y^-1 times 2y^4 z^-1)^-2/ 2yx^3 z^0 I got the numerator to be 16x^16 y^17 z and then divided by the denominator to get 8x^13y^16z
  10. Math

    I sent this in a little while back but the file got corrupted and I have to re do it and I forgot the answer please if it is not done today I fail the year. Simplify the polynomial 16x^2 + 2 + 2x - 15x^2 - 1 + 14x A:31x^2 + 16x + 1*** …

More Similar Questions