Calculus
posted by Julie .
A stone is dropped from the edge of a roof, and hits the ground with a velocity of 145 feet per second. How high (in feet) is the roof

Ke = (1/2) m v^2 = (1/2) m (145^2)
pe = m g h where g = 32.2 in ft/seconds units
32.2 m h = (1/2) m (145^2)
h = 326 feet 
vf^2=2gh
solve for h, in feet
g= 32ft/s^2 
Hey Bob, I was wondering why gravity is 32m/s^2 instead of 9.8m/s^2. Can you explain why this is?

Check the units m/s^2 and ft/s^2
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