find the maximum value of h2(g)in grams that would be expected to form by reacting 6.54g of zinc with 50ml of 0.1M of HCl.
To find the maximum value of H2(g) in grams that would be expected to form by reacting 6.54g of zinc with 50ml of 0.1M HCl, we need to use stoichiometry and the concept of limiting reactants.
1. Start by writing the balanced chemical equation for the reaction:
Zn + 2HCl -> ZnCl2 + H2
2. Calculate the number of moles of zinc (Zn) you have:
moles of Zn = mass of Zn / molar mass of Zn
In this case, moles of Zn = 6.54g / 65.38 g/mol = 0.10 mol (rounded to two decimal places)
3. Now, we need to determine the limiting reactant. The limiting reactant is the reactant that will be completely consumed first, determining the maximum amount of product that can be formed. To do this, we compare the number of moles of each reactant to the stoichiometric ratio in the balanced equation.
a. Moles of HCl = molarity of HCl x volume of HCl in liters
Moles of HCl = 0.1 M x 0.05 L = 0.005 mol
b. Compare the moles of Zn and HCl:
The stoichiometric ratio between Zn and HCl is 1:2 (from the balanced equation).
Since the moles of Zn (0.10 mol) are greater than twice the moles of HCl (0.005 mol x 2 = 0.01 mol), HCl is the limiting reactant.
4. Determine the moles of H2 gas produced using the limiting reactant:
Since 1 mole of H2 gas is produced for every 2 moles of HCl reacted, we can use the stoichiometric ratio to find the moles of H2 gas:
Moles of H2 = (0.005 mol HCl) x (1 mol H2 / 2 mol HCl) = 0.0025 mol
5. Finally, calculate the mass of H2 gas produced using the moles of H2 gas:
Mass of H2 = moles of H2 x molar mass of H2
= 0.0025 mol x 2.02 g/mol (molar mass of H2)
= 0.00505 g (rounded to five decimal places)
Therefore, the maximum value of H2(g) in grams that would be expected to form is approximately 0.00505 grams.