How much CuSO4-5H2O is needed to make up 500 ml of 2.5 M CuSO4
molarity=moles/volume
moles=molarity*volume=2.5*.5=1.25 moles
what is the mass of 1.25moles of copperII sulfate pentahydrate?
To determine the amount of CuSO4-5H2O needed to make up 500 ml of 2.5 M CuSO4, we need to calculate the moles of CuSO4 required first.
Step 1: Convert the volume to liters.
500 ml is equal to 500/1000 = 0.5 liters.
Step 2: Calculate the moles.
The molarity (M) is defined as moles of solute per liter of solution. As we want to make 2.5 M CuSO4, we multiply the molarity by the volume:
moles of CuSO4 = Molarity × volume
moles of CuSO4 = 2.5 mol/L × 0.5 L
moles of CuSO4 = 1.25 moles
Step 3: Convert the moles of CuSO4 to moles of CuSO4-5H2O.
CuSO4 and CuSO4-5H2O have the same molar mass. However, CuSO4-5H2O contains 5 molecules of water, so we need to account for that.
The molar mass of CuSO4 is 63.55 + (32.07 + 4 × 16.00) = 159.61 g/mol.
Therefore, 159.61 g of CuSO4 is equivalent to 1 mole.
Step 4: Calculate the mass of CuSO4-5H2O required.
mass of CuSO4-5H2O = moles of CuSO4 × molar mass of CuSO4-5H2O
mass of CuSO4-5H2O = 1.25 moles × 159.61 g/mol
mass of CuSO4-5H2O = 199.51 g
Therefore, to make up 500 ml of 2.5 M CuSO4, you will need 199.51 grams of CuSO4-5H2O.
To determine the amount of CuSO4-5H2O needed to make up 500 ml of 2.5 M CuSO4 solution, we need to consider the molar mass of CuSO4-5H2O and the desired concentration.
The molar mass of CuSO4-5H2O can be calculated as follows:
- The molar mass of Cu is 63.55 g/mol.
- The molar mass of S is 32.07 g/mol.
- The molar mass of O is 16.00 g/mol.
- The molar mass of H is 1.01 g/mol.
- And there are five water molecules (H2O) in the compound, so the molar mass of H2O is 18.02 g/mol.
Therefore, the molar mass of CuSO4-5H2O is (63.55 + 32.07 + (4 * 16.00)) + (5 * 18.02) = 249.70 g/mol.
To calculate the amount of CuSO4-5H2O needed, we can use the formula:
Amount (in moles) = Concentration (in moles/liter) * Volume (in liters)
First, let's convert the volume from milliliters (ml) to liters (L):
Volume = 500 ml * (1 L / 1000 ml) = 0.5 L
Now we can substitute the known values into the formula:
Amount (in moles) = 2.5 moles/L * 0.5 L = 1.25 moles
Finally, using the molar mass of CuSO4-5H2O, we can calculate the mass (in grams) of CuSO4-5H2O needed:
Mass (in grams) = Amount (in moles) * Molar mass = 1.25 moles * 249.70 g/mol
Thus, the amount of CuSO4-5H2O needed to make up 500 ml of 2.5 M CuSO4 solution is approximately the calculated mass (in grams).