A clock has its second hand 2 cm long. What will the average velocity of the tip of the second hand in 15 seconds.
That depends upon the interval of time that you are averaging over. Is it a 15 second interval? Where was the second had at the start of the interval? You will need to know that in order to specify the direction of the average velocity.
Draw a line between the positions of the end of the second hand at the beginning and end of the interval. Then divide the length of that line by 15 seconds, the interval length.
The number you get will be the average velocity in units of cm/s
A prmjectile is lanched on horizontal plane. Variation of slop of trajectory of projectile. Where m=0 to 1 and t=0 to 10 s. What will be horizotal range?
To find the average velocity of the tip of the second hand, we need to determine the distance traveled by the tip of the hand in 15 seconds.
First, let's calculate the circumference of the circle traced by the tip of the second hand. Since the second hand is 2 cm long, the circumference can be found using the formula:
C = 2 * π * r
Where r is the length of the second hand, which is 2 cm.
C = 2 * π * 2
C = 4π cm
So, the tip of the second hand traces a distance of 4π cm in one minute.
Now, let's calculate the distance traveled in 15 seconds. Since there are 60 seconds in 1 minute, we can use the proportion:
4π cm -> 60 seconds
X cm -> 15 seconds
Using the proportion:
X = (15 * 4π) / 60
= (4π / 4) cm
= π cm
Therefore, the average velocity of the tip of the second hand in 15 seconds is π cm.