physics

posted by .

If velocity v of particle moving in straight line is related with distance travelled S as v=2(1+S)^1/2. What will the acceleration of the particle?

  • physics -

    The problem I have here is units.

    velocity is distance/time, and your equation is sqrt distance. Hmmmm.

    Assuming somehow that is fixed in magic land, then

    acceleration= dv/dt=
    (1+s)^-1/2 * ds/dt but ds/dt is V so

    acceleration= 2 (1+s)^0=2

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Maths mst

    Question – 3: Consider a particle moving according to the velocity function, v(t) = 2a-3exp(-2t)+2/t+2,for t>0. (a) If the net distance,d,covered by the particle in the time interval,[0,3],is 20,find the value of a. What is the …
  2. Calculus-particle motion

    1. A particle is moving on the x-axis (or any number line) Its position x(t), or distance from the origin, at the time t is given by x(t)=4t^3-16t^2+15t. t is greater than or equal to 0 a.) Where is the particle when it is at rest?
  3. calculus

    A particle moves in a straight line with velocity given by v(t) =sin t metres per second. Find the total distance travelled by the particle in the first 4 seconds of motion
  4. Calculus

    The position of a particle moving on a horizontal line is given by s(t)=2t^3-15t^2+24t-5, where s is measured in feet and t in seconds. a: What is the initial position of the particle?
  5. physics,dynamics

    The acceleration of a particle along a straight line is defined by a = (2t - 9) m/s2, where t is in seconds. At t = 0, s = 1 m and v = 10 m/s. When t = 9 s, determine (a) the particle’s position, (b) the total distance traveled, …
  6. Physics

    A particle is moving along a straight line and its position is given by the relation x=( t3-6t2-15t+40)mm. Find:- (a). The time at which velocity is zero. (b). Position & displacement of the particle at that point. (c). Acceleration …
  7. math

    A particle moves along straight line such that its displacement S meters from a given point is S = t^3 – 5t^2 + 4 whee t is time in seconds. Find (a) The displacement of particle at t = 5 (b) The velocity of the particle when t = …
  8. Maths

    a particle starts from rest at o and moves in a straight line so that t seconds after, its velocity vm/s is given by v=2t-t^2. given that particle comes instantanuously at rest at p. Find i) time taken to reach p?
  9. physics

    A particle is moving along a straight line and its position is given by the relation x=( t3-6t2-15t+40)mm. Find:- (a). The time at which velocity is zero. (b). Position & displacement of the particle at that point. (c). Acceleration …
  10. physics

    A particle is moving along a straight line and its position is given by the relation x=(t3- 6t2- 15t+40) m FIND a) The time at which velocity is Zero, b) Position and displacement of the particle at that point. c) Acceleration for …

More Similar Questions