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a car moving with constant acceleration covered a distance of 50 metres between two points in 5 seconds. if the velocity of the car at the second point is 16 metres per second. what is the acceleration of the car. what the velocity of the car at the first point

  • physics -

    average seed = 50/5 = 10 m/s
    let Vi = speed at first point
    10 = (Vi +16)/2
    20 = Vi + 16
    Vi = 4 m/s

    a = change in velocity/ change in time = (16-4)/5 = 12/5 = 2.4 m/s^2

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