chemistry

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The reaction of calcium bicarbonate, Ca(HCO3)2 with hydrochloric acid, HCl, produces a solution of CaCl2, gaseous carbon dioxide, CO2, and water, H2O. Write a balanced chemical equation for this reaction and determine the volume of CO2, in mL, that forms at 30.0 oC and 0.660 atm upon reacting 40.3 mL of 0.200 M Ca(HCO3)2 with excess HCl.

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    I. balanced equation:
    Ca(HCO3)2 + HCl ->CaCl2 + 2 H2O + 2 CO2

    II. find moles of Ca(HCO3)2 :

    40.3 mL x 1 L/1000mL x 0.2 mole/L =
    8.06 x 10^-3 moles Ca(HCO3)2

    III. find moles CO2 :
    [8.06 x 10^-3] moles Ca(HCO3)2 x
    2 moles CO2/1 mole Ca(HCO3)2 =
    1.61 x 10^-2 moles CO2

    IV. find volume from PV=nRT
    V= nRT/P
    V = (1.61 x10^-2)(0.082)(273 +30)
    all divided by 0.660) = 0.606 L =606 mL

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