# statistics

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Is my answer correct.

Q. How many megabytes of memory would be required to store an uncompressed 2-minute video file which is played at 24 frames per second, with a frame size of 320 × 240 pixels using a 24-bit per pixel colour model?

A. 320*240*24 = 1843200 bytes
since, 24*120 = 2880 sec

therefore, 2880*1843200 = 5308416000bytes
~ 5062.5 MB

• statistics -

=320*240*(24/8)[8 bits is equal to 1 byte]
=320*240*3
=230400 bytes
since,
24*120=2880 frames
therefore, 2880*230400 bytes
which is 663 MB ~ 633MB

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