determine the number of grams of KCl salt contained in 1.25L of a 5.00%(W/V) KCl(aq)
5.00% KCl w/v means 5.00g KCl/100 mL soln which is 5.00 x (1,250/100) = ?? g KCl in 1.25L soln.
How many grams of KCl are produced when 6.00 moles of KClO3 decomposes into KCl and O2?
To determine the number of grams of KCl salt contained in 1.25L of a 5.00% (W/V) KCl(aq) solution, we need to apply the concept of percent concentration.
First, let's understand what 5.00% (W/V) means. It indicates that there are 5.00 grams of KCl dissolved in 100 mL (or 100 grams) of solution. This information will help us calculate the concentration of KCl in the given volume.
To find the concentration in the original solution, we can set up a proportion using the given percentage:
% concentration = (grams of solute / mL of solution) * 100
Now, let's calculate the grams of KCl salt in 1.25L of the solution:
Step 1: Convert 1.25L to mL:
1.25L * 1000 mL/L = 1250 mL
Step 2: Set up a proportion to find the grams of KCl:
5.00 grams / 100 mL = X grams / 1250 mL
X = 5.00 grams * (1250 mL / 100 mL)
X = 62.5 grams
Therefore, there are 62.5 grams of KCl salt contained in 1.25L of a 5.00% (W/V) KCl(aq) solution.