how many mL of 2.0 M NaOH are required to get 100 g of NaOH?
To find out how many milliliters (mL) of a 2.0 M (molar) NaOH solution are required to obtain 100 grams (g) of NaOH, you need to use the equation:
Molarity (M) = moles (mol) / volume (L)
Firstly, we need to calculate the number of moles of NaOH using its molar mass. The molar mass of NaOH is 22.99 g/mol (Na) + 16.00 g/mol (O) + 1.01 g/mol (H) = 39.99 g/mol.
To find the number of moles, we divide the given mass (100 g) by the molar mass (39.99 g/mol):
moles = mass / molar mass
moles = 100 g / 39.99 g/mol
moles ≈ 2.5006 mol
Now, we can use the molarity equation to determine the volume of the 2.0 M NaOH solution required:
Molarity = moles / volume
2.0 M = 2.5006 mol / volume
Rearranging the equation to solve for volume:
volume = moles / Molarity
volume = 2.5006 mol / 2.0 M
Therefore, the volume of the 2.0 M NaOH solution required to obtain 100 g of NaOH is approximately:
volume = 1.2503 L
Since there are 1000 mL in 1 L, we can convert the volume from liters to milliliters by multiplying by 1000:
volume = 1.2503 L * 1000 mL/L
volume ≈ 1250.3 mL
So, approximately 1250.3 mL of a 2.0 M NaOH solution will be required to obtain 100 g of NaOH.