precalc
posted by Diana .
How would you find the inverse of these two functions: f(x)=4/(x4)^2 and
f(x)=x^28x+16
could you please show me step by step i have been trying to figure it out for hours.

first one:
y = 4/(x4)^2
inverse is
x = 4/(y4)^2
solving this for y .....
(y4)^2 = 4/x
y  4 = ± 2/√x
y = 4 ± 2/√x
2nd .....
inverse is
x = y^2  8y + 16
y^2  8y + 16  x = 0
use the quadratic equation
where a=1, b=8 and c = 16x to solve for y 
thanks i got the first one now!
for the second one I used the quadratic eqn and got 4 but that is not the answer? 
y = (8 ± √(644(1)(16x))/2
= (8 ± √(4x) )/2
= (8 ± 2√x)/2
= 4 ± √x
check: let x = 3 into the first
y = 9  24 + 16 = 1
put x = 1 into the second:
y = 4 ± √1 = 5 or 3
notice the the inverse of each of the equations is not a function.