calculus
posted by Anonymous .
h(x)= integral from (1, 1/x) arctan(2t)dt
part 1: let U= 1/x and du= ?
> using u=1/x, we can write h(x)= integral from (1, 1/x) arctan (2t)dt as h(u)= integral from (1,u) arctan(2t)dt and h'(u)= arctan (2)
Part 2: By the chain Rule, for functions h(u) and u(x), we have:
> dh/dx= ______ du/dx
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