What is the number of moles of gas contained in a 3 L vessel at 300 K with a pressure of 1.50 atm? (Given: R = 0.08205 L∙atm/mol∙K)
Use PV = nRT
.18mol
#CAPEHENLOPENHIGHSCHOOL
TWILIGHT/DAYLIGHT/SUMMER SCHOOL
To find the number of moles of gas contained in a 3 L vessel at 300 K with a pressure of 1.50 atm, you can use the Ideal Gas Law equation:
PV = nRT, where:
P = pressure = 1.50 atm
V = volume = 3 L
n = number of moles (what we need to find)
R = ideal gas constant = 0.08205 L∙atm/mol∙K
T = temperature in Kelvin = 300 K
First, let's rearrange the equation to solve for n:
n = PV / RT
Now, we can substitute the given values:
n = (1.50 atm) * (3 L) / (0.08205 L∙atm/mol∙K * 300 K)
Simplifying this gives:
n = 4.5 atm∙L / (24.615 L∙atm/mol∙K)
n = 0.183 mol
Therefore, there are 0.183 moles of gas contained in the 3 L vessel.
To find the number of moles of gas contained in a vessel, we can use the ideal gas law equation:
PV = nRT
Where:
P = Pressure of the gas (in atm)
V = Volume of the gas (in liters)
n = Number of moles of gas
R = Ideal gas constant (in L∙atm/mol∙K)
T = Temperature of the gas (in Kelvin)
We are given:
P = 1.50 atm
V = 3 L
R = 0.08205 L∙atm/mol∙K
T = 300 K
Plugging these values into the ideal gas law equation, we have:
(1.50 atm)(3 L) = n(0.08205 L∙atm/mol∙K)(300 K)
Simplifying this equation, we get:
4.50 atm∙L = 24.615 n
Now, we can solve for n:
n = (4.50 atm∙L) / 24.615
Calculating this out, we find:
n ≈ 0.183 moles
Therefore, the number of moles of gas contained in the 3 L vessel is approximately 0.183 moles.