A person in a kayak starts paddling, and it accelerates from 0 to 0.498 m/s in a distance of 0.554m. If the combined mass of the person and the kayak is 62.6, what is the magnitude of the net force acting on the kayak?
Use the formula
F = m a
to get the force in Newtons.
In this case, m is the combined mass of kayak and the person paddling.
You neglected to provide units for the combined mass. I assume it is kilograms.
For the acceleration, a, assume uniform acceleration, in which case
Vfinal = sqrt(2aX)
a = Vfinal^2/(2X)
X = 0.554 m
To find the magnitude of the net force acting on the kayak, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.
First, we can calculate the acceleration of the kayak using the formula:
acceleration = (final velocity - initial velocity) / distance
Given:
Initial velocity (u) = 0 m/s
Final velocity (v) = 0.498 m/s
Distance (s) = 0.554 m
Substituting these values into the formula, we get:
acceleration = (0.498 m/s - 0 m/s) / 0.554 m
acceleration = 0.498 m/s / 0.554 m
acceleration ≈ 0.899 m/s²
Next, we can use the mass of the person and the kayak (62.6 kg) and the calculated acceleration (0.899 m/s²) in the formula for net force:
net force = mass * acceleration
Substituting these values into the formula, we get:
net force = 62.6 kg * 0.899 m/s²
net force ≈ 56.12 N
Therefore, the magnitude of the net force acting on the kayak is approximately 56.12 Newtons.