the density of water is 1gm/ml. what is the molarity of 1 drop of water?
Depends upon how many drops of water are in 1 mL. With a good teflon tipped buret, there are about 30 drops which makes each drop about 0.0333 mL.
That makes a drop have a mass of 0.0333 grams and that is 0.0333/18.015 moles or 0.00185moles/L or 0.00185/0.00003333 = 55.51 M which may be too many significant figures but you can take care of that.
I think a much easier route is to forget the 1 drop business. The molarity of 1 drop is the same as M of 10 drops or a L or a washtub of water.
1L H2O has a mass of 1000g (at the 1g/mL density level) and 1000/18.015 = 55.51 moles/L
To determine the molarity of one drop of water, we need to consider the volume of a drop of water and the molecular weight of water.
The volume of a drop of water can vary depending on several factors such as temperature, dropper size, and surface tension. On average, a drop of water is estimated to be around 0.05 mL (though this can vary).
Next, we need to calculate the number of moles of water in one drop.
The molecular weight of water (H₂O) is 18.01528 g/mol, which can be obtained by adding the atomic weights of two hydrogen atoms (1.00784 g/mol each) and one oxygen atom (15.999 g/mol).
Now, we can calculate the molarity using the equation: Molarity (M) = moles/volume (in liters)
1 drop of water = 0.05 mL = 0.05/1000 = 0.00005 L (converting mL to L)
Moles of water = mass/molecular weight = 1 g/18.01528 g/mol = 0.0554 moles
Molarity = 0.0554 moles / 0.00005 L = 1108 M
Therefore, the molarity of 1 drop of water is approximately 1108 M. Please note that this value is an estimation based on average drop volume, and the actual molarity may vary depending on the size of the drop.