statistics
posted by elizabeth6 .
This is what my teacher gave us I guess he want us to figture out the question.
cost/mile 0.08 normal distribution
means=.08
standard deviation=0.2
Car life 5 uniform distribution( minmun=2, max=8
annual milage =900 triangular distribution(min=3700
most likely =9000
max=14500
annual cost= 3600
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