# algebra 21

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Solve the equation. If necessary, round to thousandths.
3^(2x + 1) = 27

• algebra 2 -

my bad supposed to say algebra 2

• algebra 21 -

3^(2x+1) = 3^3
2x+1 = 3
2x=2
x=1

• algebra 21 -

Substitute (2x + 1) for y.

3^y = 27
y = 3

Back-substitute.

2x + 1 = 3
x = 1

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