Solve the equation. If necessary, round to thousandths.

3^(2x + 1) = 27

3^?=27

3^3=27

drop the bases
2x+1=3
x=2

I believe Capreeca is wrong on this one.

2x+1=3
2x=2
x=1

To solve the equation 3^(2x + 1) = 27, we can start by recognizing that 3^3 = 27. Therefore, we can rewrite the equation as:

3^(2x + 1) = 3^3

Since the bases are the same, we can equate the powers:

2x + 1 = 3

Now, we can solve for x.

Subtract 1 from both sides of the equation:

2x = 3 - 1
2x = 2

Divide both sides of the equation by 2:

x = 2/2
x = 1

Therefore, the solution to the equation is x = 1.