How many moles of C are needed to react with 85.5 moles of Al2O3 ?
Here is a worked example.
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To determine how many moles of carbon (C) are needed to react with 85.5 moles of aluminum oxide (Al2O3), we first need to look at the balanced chemical equation for the reaction between carbon and aluminum oxide.
The balanced chemical equation for the reaction is:
3C + 2Al2O3 → 4Al + 3CO2
According to the balanced equation, we need 3 moles of carbon (C) for every 2 moles of aluminum oxide (Al2O3).
To find out how many moles of C are needed, we can set up a proportion using the balanced equation:
3 moles C / 2 moles Al2O3 = x moles C / 85.5 moles Al2O3
Cross-multiplying the proportions, we have:
3 moles C * 85.5 moles Al2O3 = 2 moles Al2O3 * x moles C
Simplifying the equation:
256.5 moles C = 2 moles Al2O3 * x moles C
Dividing both sides of the equation by 2 moles Al2O3, we have:
x moles C = 256.5 moles C / 2 moles Al2O3
Performing the calculation, we find:
x = 128.25 moles C
Therefore, 128.25 moles of carbon (C) are needed to react with 85.5 moles of aluminum oxide (Al2O3).