I need help with rearranging this equation to isolate c
a=b((1/c)-(1/d))
I got this (a/b)+(1/d)=(1/c) but I don't know the last step with the reciprocal. Could someone please help, thank you
First, write a/b + 1/d with a common denominator.
ad/bd + b/bd
(ad + b)/bd
You can easily take the reciprocal from here.
the computer said my answer was correct like this (a/b)+(1/d)=(1/c) but I need to do the reciprocal of (1/c) and I don't know how that will look in the equation
Here is how the equation should look:
a/b + 1/d = 1/c
ad/bd + b/bd = 1/c
(ad + b)/bd = 1/c
Taking the reciprocal of both sides...
bd/(ad + b) = c
thank you. It worked
You're welcome.
To isolate "c" in the equation "a = b((1/c) - (1/d))," you've correctly reached the expression (a/b) + (1/d) = (1/c). The next step involves taking the reciprocal of both sides.
Reciprocal of (a/b) + (1/d) can be found by inverting the expression, flipping the numerator and denominator. This gives us 1 / [(a/b) + (1/d)].
To simplify the right-hand side, we need to find a common denominator. The least common denominator (LCD) of b and d is bd.
Now, we can rewrite the equation as:
1 / [(a/b) + (1/d)] = 1 / c
To simplify further, let's combine the fractions on the right-hand side:
[(a/b) + (1/d)] / bd = 1 / c
Now, we can take the reciprocal of both sides to isolate "c":
c = bd / [(a/b) + (1/d)]
Thus, the rearranged equation to isolate "c" is:
c = bd / [(a/b) + (1/d)]