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The height of a projectile fired upward is given by the formula
s = v0t − 16t2,
where s is the height in feet,
v0
is the initial velocity, and t is the time in seconds. Find the time for a projectile to reach a height of 96 ft if it has an initial velocity of 128 ft/s. Round to the nearest hundredth of a second.

  • math -

    so you are solving

    96 = 128 - 16t^2
    16t^2 = 32
    t = √2

    I will leave the rounding to you.

  • ignore last reply - math -

    should have been

    96 = 128t - 16t^2
    16t^2 - 128t + 96 = 0
    t^2 - 8t + 6 = 0
    t = 4 + √10 or 4 - √10

    There are two possible answers, since the height of 96 feet is reached on its upwards flight, and then again when it comes back down.

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