When 15.0 g of steam drops in temperature from 275.0 degrees c to 250.0 degrees, how much heat energy is released
To calculate the amount of heat energy released when the temperature of steam drops, you can use the equation:
Q = mcΔT
Where:
Q = heat energy
m = mass of the steam
c = specific heat capacity of steam
ΔT = change in temperature
In this case, you are given:
m = 15.0 g
ΔT = 250.0 °C - 275.0 °C = -25.0 °C (since the temperature is dropping)
To use the equation, we need to find the specific heat capacity of steam. The specific heat capacity of water is commonly used as an approximation for steam. The specific heat capacity of water is 4.184 J/g°C.
Now, we can substitute the values into the equation:
Q = (15.0 g)(4.184 J/g°C)(-25.0 °C)
Q = -1578 J
Therefore, approximately 1578 J of heat energy is released when 15.0 g of steam drops in temperature from 275.0 °C to 250.0 °C.