Post a New Question

Physics

posted by .

I am having trouble with the last portion of this question. If someone can help me, I would sincerely appreciate it.

A bicycle wheel has a radius R = 32.0 cm and a mass M = 1.82 kg which you may assume to be concentrated on the outside radius. A resistive force f = 147 N (due to the ground) is applied to the rim of the tire. A force F is applied to the sprocket at radius r such that the wheel has an angular acceleration of a = 4.50 rad/s^2. The tire does not slip.

a) If the sprocket radius is 4.53 cm, what is the force F (N)?

(mr^2)(4.5) = (r)(F)- (147)(.32)
(1.82)(.32^2)(4.5) = (.0453)(F)-(147)(.32)
= 1056.9

b) If the sprocket radius is 2.88 cm, what is the force F(N)?

(1.82)(.32^2)(4.5) = (.0288)(F)-(147)(.32) = 1662.45

c) What is the combined mass of the bicycle and rider (kg)?
I am not sure how to do this last part

The correct answer is 102 kg
No one has answered this question yet.

  • Physics -

    Ok, the last part, you have a force on the sprocket producing a net force and acceleration.
    assume the force is transmitted as a lever to the ground...

    F(sprocketradius/wheel radius)-147*.32= mass*acceleration

    but acceleration= 4.5*wheel radius

    F(sprocketradius)-147*wheelradius=mass*
    4.5*wheel radius

    or mass= (F*sproketradius/wheelradius-147)/4.5 = mass
    mass= (1662*.0288/.32 -147)/4.5=99.7kg

    check all calculations

  • Physics -

    F = ma for the whole bike as a unit. The force F that is causing the bike to move is your resistive force 147N. a = R*alpha, so you should have m=F/R*alpha so m = 147/(.32*4.5) = 102.083 which is the answer given by OP as being correct.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Physics

    Question related to a bicycle dynamo and a wheel. Why a current flows through the bicycle lamp when the wheel of the bicycle turns?
  2. Physics

    I am having trouble with the last portion of this question. If someone can help me, I would sincerely appreciate it. A bicycle wheel has a radius R = 32.0 cm and a mass M = 1.82 kg which you may assume to be concentrated on the outside …
  3. physics

    The moment of inertia of a 0.98 kg bicycle wheel rotating about its center is 0.13 km-m^2. What is the radius of the wheel?
  4. trigonometry

    The sprockets and chain of a bicycle are shown in the figure. The pedal sprocket has a radius of 4 in., the wheel sprocket a radius of 2 in., and the wheel a radius of 13 in. The cyclist pedals at 45 rpm. (a) Find the angular speed …
  5. physics

    A bicycle wheel has a diameter of 57.7 cm and a mass of 2.66 kg. The bicycle is placed on a stationary stand and a resistive force of 156 N is applied tangent to the rim of the tire. Assume that the wheel is a hoop with all of the …
  6. Physics

    Assume that all of the mass of a bicycle wheel is concentrated at its rim. Such a wheel of mass 1.2 kg and radius 30 cm starts from rest at the top of a hill 100m long and inclined at 20 degrees to the horizontal. What will be the …
  7. Physics

    You are holding the axle of a bicycle wheel with radius 35 cm and mass 1 kg. You get the wheel spinning at a rate of 55 rpm and then stop it by pressing the tire against the pavement. You notice that it takes 2.0 s for the wheel to …
  8. Physics

    A bicycle wheel has a diameter of 47.6 cm and a mass of 0.809 kg. The bicycle is placed on a stationary stand on rollers and a resistive force of 60.1 N is applied to the rim of the tire. Assume all the mass of the wheel is concentrated …
  9. Physics

    A bicycle wheel has a diameter of 47.6 cm and a mass of 0.809 kg. The bicycle is placed on a stationary stand on rollers and a resistive force of 60.1 N is applied to the rim of the tire. Assume all the mass of the wheel is concentrated …
  10. physics

    A bicycle is rolling down a circular portion of a path; this portion of the path has a radius of 8.73 m. As the drawing illustrates, the angular displacement of the bicycle is θ = 0.979 rad. What is the angle (in radians) through …

More Similar Questions

Post a New Question