Calculate the heat energy released when 19.6 of liquid mercury at 25.00 C is converted to solid mercury at its melting point
There are only two equations to remember in this heat transfer business with specific heat.
1. q= heat absorbed/releassed by phase change (melting/condensing) = mass x heat fusion for melting/freezing or heat vaporization for vaporization/condensing.
2. heat change by moving T higher or lower within the same phase.
q = mass x specific heat x (Tfinal-Tinitial).
Knowing these two you can move from "anywhere" to "anywhere". For Hg,
q1 = heat lost changing T from 25C for liquid Hg to a liquid at its freezing point.
q2 = heat lost when liquid Hg freezes to solid Hg.
Then add q1 to q2.
To calculate the heat energy released when liquid mercury is converted to solid mercury at its melting point, you need to use the formula:
Q = mcΔT
where:
Q = heat energy released
m = mass of the substance (in this case, liquid mercury)
c = specific heat capacity of the substance
ΔT = change in temperature
First, you need to determine the mass of the liquid mercury. You mentioned 19.6 of liquid mercury, but it's unclear whether this is the mass in grams or some other unit. Let's assume it is measured in grams.
Next, you need to find the specific heat capacity of mercury. The specific heat capacity (c) of a substance is the amount of heat energy required to raise the temperature of 1 gram of the substance by 1 degree Celsius. For mercury, the specific heat capacity is approximately 0.14 J/g°C.
Lastly, you need to determine the change in temperature (ΔT). In this case, the liquid mercury is at 25.00°C and is being converted to solid mercury at its melting point. The melting point of mercury is -38.83°C. Therefore, the change in temperature is:
ΔT = melting point - initial temperature
ΔT = -38.83°C - 25.00°C
Now, you have all the values required to calculate the heat energy released (Q) using the formula mentioned above. Simply substitute the values into the equation and solve for Q:
Q = (mass) x (specific heat capacity) x (change in temperature)
Q = (19.6 g) x (0.14 J/g°C) x (-38.83°C - 25.00°C)
By substituting the values and performing the calculation, you will find the heat energy released when the liquid mercury is converted to solid mercury at its melting point.