How many moles of oxygen are in 3.45 mol of diphosphorus pentoxide?
options:
5.75 mol O
13.5 mol O
6.90 mol O
3.45 mol O
17.3 mol O
There are 5 moles oxygen atoms in 1 mole P2O5; therefore, there must be 3.45 x 5 = ?? moles oxygen in 3.45 moles.
3.45 mol x 5 mol O/1 mol P2O5=
17.3 mol of Oxygen
Well, if you've got 3.45 mol of diphosphorus pentoxide, it means you've got a whole bunch of oxygen atoms hanging around! Diphosphorus pentoxide, or P2O5, has a ratio of 2 phosphorus atoms to 5 oxygen atoms. So, for every mole of P2O5, you've got 5 moles of O. Since you've got 3.45 mol of P2O5, just multiply that by 5 and you'll have your answer! That's 17.25 mol of oxygen, which we can round up to 17.3 mol O. So sit back and relax, because you've got a whole lot of oxygen moles to keep you company!
To determine how many moles of oxygen are in 3.45 mol of diphosphorus pentoxide, we need to first find the molar ratio of oxygen to diphosphorus pentoxide.
The chemical formula for diphosphorus pentoxide is P2O5. From the formula, we see that there are 5 oxygen atoms in one molecule of diphosphorus pentoxide.
So, the molar ratio of oxygen to diphosphorus pentoxide is 5 moles of O / 1 mole of P2O5.
To find the number of moles of oxygen in 3.45 mol of P2O5, we can set up the following proportion:
(5 mol O / 1 mol P2O5) = (x mol O / 3.45 mol P2O5)
Cross-multiplying and solving for x, we get:
5 mol O = x mol O * 3.45 mol P2O5
x mol O = (5 mol O * 3.45 mol P2O5) / 1 mol P2O5
x mol O = 17.25 mol O
Therefore, there are 17.3 mol O in 3.45 mol of diphosphorus pentoxide.
The correct option is:
17.3 mol O
To determine the number of moles of oxygen in 3.45 mol of diphosphorus pentoxide (P2O5), we need to consider the balanced chemical equation for the reaction involving diphosphorus pentoxide.
The chemical formula for diphosphorus pentoxide is P2O5, which implies that there are two moles of phosphorus (P) and five moles of oxygen (O) in one mole of diphosphorus pentoxide. Therefore, the molar ratio between P2O5 and O is 5:1.
To find the number of moles of oxygen in 3.45 mol of diphosphorus pentoxide, we can set up a proportion:
(3.45 mol P2O5) / (1 mol P2O5) = (x mol O) / (5 mol O)
Cross multiplying the equation gives us:
3.45 mol P2O5 * 5 mol O = x mol O * 1 mol P2O5
x mol O = (3.45 mol P2O5 * 5 mol O) / (1 mol P2O5)
x mol O = 17.25 mol O
Rounding it to the correct number of significant figures, we get:
x ≈ 17.3 mol O
Therefore, the correct option is 17.3 mol O.