Shawn

posted by .

How many milliliters of 0.355 M NaF solution are needed to react completely with 24.6 mL of 0.216 M CaCl2 solution? How many grams of CaF2 will be formed? The reaction is

CaCl2(aq) + 2NaF(aq) → CaF2(s) + 2NaCl(aq)

  • Shawn -

    According to your balanced equation, each mole of CaCl2 needs one mole of NaF.

    Moles of CaCl2: .0246*.216

    volume of NaF=that/.355 in liters.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    What is the molar solubility of CaF2 if o,1o mol of NaF are added to 1.0L of a saturated solution of CaF2?
  2. chem

    158.5 mL of a AgNO3 solution at 5.0M was combined with a 3.5M CaCl2 solution. 110.5g of AgCl was recovered. Given that the CaCl2 is the limiting reagent, how many milliliters of the 3.5M CaCl2 solution was used?
  3. Chemistry

    158.5 mL of a AgNO3 solution at 5.0M was combined with a 3.5M CaCl2 solution. 110.5g of AgCl was recovered. Given that the CaCl2 is the limiting reagent, how many milliliters of the 3.5M CaCl2 solution was used?
  4. Chemistry

    2NaF + CaCl2 ¨ CaF2 + 2NaCl An excess of 0.20 M NaF is used to precipitate the calcium ions from a 50.0 mL sample of a calcium chloride solution. What is the concentration of the original calcium chloride solution?
  5. Chemistry

    How many milliliters of 0.277 M AgNO3 solution are needed to react completely with 47.1 mL of 0.278 M NaCl solution?
  6. chemistry

    The Ksp for calcium fluoride (CaF2) is 3.9 x 10^–11 at 25°C. How many moles of solid NaF must be added to 1.00 L of 0.100 M CaCl2 in order to precipitate CaF2?
  7. chemistry

    Given a saturated solution of CaF2, write the ionic equilibrium and use it to calculate the solubility of CaF2. My answers for the ionic equation and ksp values are CaF2(s)<->Ca2+(aq)+ 2F-(aq) Ksp= [Ca2+][F-]2 ksp=2.02*10^-4 …
  8. chem hwk help!

    Given the following reaction: 3 CaCl2 + 2 H3PO4 Ca3(PO4)2 + 6 HCl How many grams of H3PO4 are needed to react completely with 1.837 g of CaCl2?
  9. Chemistry

    A solution of calcium nitrate, Ca(NO3)2, reacts with a solution of ammonium fluoride, NH4F, to form solid calcium fluoride, CaF2, and ammonium nitrate, NH4NO3(aq). When 45.00 mL of 4.8724 x 10-1 M Ca(NO3)2 solution was added to 60.00 …
  10. Chemistry

    How mush CaCl2, in grams, is needed to make 2.0 L of a 3.5M solution?

More Similar Questions