physics
posted by Kate .
A 5.0 m diameter merrygoround is initially turning with a 4.6 s period. What is the speed of a child on the rim?

T = (2pir)/v with T being the period, r being the radius, and v being the speed. Don't forget that radius is half the diameter.
So, v*4.6s = 2*pi*2.5m
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