Benzene, C6H6, is a known carcinogen that burns in air according to the following unbalanced equation:
C6H6(l) + O2(g) CO2(g) + H2O(g)
a. What is the mole ratio of O2 to C6H6?
b. How many moles of O2 are required to react with each mole of C6H6?
c. How many moles of O2 are required to react with 0.38 mol of C6H6?
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To find the mole ratio of O2 to C6H6, we can examine the coefficients of the balanced equation:
C6H6(l) + O2(g) -> CO2(g) + H2O(g)
a. The balanced equation shows that the mole ratio of O2 to C6H6 is 1:1. This means that for every 1 mole of C6H6, you need 1 mole of O2.
b. Since the mole ratio is 1:1, 1 mole of O2 is required to react with each mole of C6H6.
c. To calculate the number of moles of O2 required to react with 0.38 mol of C6H6, we use the mole ratio obtained in part a.
Since the mole ratio of O2 to C6H6 is 1:1, we need an equal amount of moles of O2 for the reaction. Therefore, 0.38 mol of O2 is required to react with 0.38 mol of C6H6.
a. To find the mole ratio of O2 to C6H6, we can observe the balanced equation:
C6H6(l) + O2(g) → CO2(g) + H2O(g)
According to the equation, for every 1 mole of C6H6, we need some number of moles of O2. The coefficient in front of O2 in the balanced equation is 1. Therefore, the mole ratio of O2 to C6H6 is 1:1.
b. To determine how many moles of O2 are required to react with each mole of C6H6, we can refer to the balanced equation:
C6H6(l) + O2(g) → CO2(g) + H2O(g)
From the balanced equation, it is evident that 1 mole of C6H6 reacts with 1 mole of O2. Therefore, 1 mole of O2 is required to react with each mole of C6H6.
c. If we have 0.38 mol of C6H6, we can use the mole ratio from part a to determine how many moles of O2 are required.
Given: 0.38 mol C6H6
Using the mole ratio from part a (1:1), we can conclude that the number of moles of O2 required will also be 0.38 mol. So, 0.38 moles of O2 are required to react with 0.38 mol of C6H6.
Balance the equation and that will answer b and c.
2C6H6 + 15O2 ==> 12CO2 +6H2O