An elevator starts from rest with a constant upward acceleration and moves 1m in the first 1.4 s. A passenger in the elevator is holding a 6.3 kg bundle at the end of a vertical chord. what is the tension in the chord as the elevator accelerates? The acceleration of gravity is 9.8 m/s^2. Answer in units of N

Im not sure if i solved this right, but here is my work:

6.3(9.8)=61.74 N

To solve this problem, we can apply Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration.

At the beginning, when the elevator starts from rest, the only force acting on the bundle is its weight, which is given by W = m * g, where m is the mass of the bundle and g is the acceleration due to gravity.

Therefore, at the start:
W1 = m * g = 6.3 kg * 9.8 m/s^2 = 61.74 N

Next, we need to determine the acceleration of the elevator. We are given that the elevator moves 1m in the first 1.4 seconds. To find the acceleration, we can use the formula:

s = ut + 0.5 * a * t^2

where s is the displacement, u is the initial velocity (which is 0 as the elevator starts from rest), a is the acceleration, and t is the time.

Plugging in the values:
1m = 0 * 1.4s + 0.5 * a * (1.4s)^2

Simplifying:
1m = 0 + 0.5 * a * 1.96s^2
1m = 0.98 * a * s^2

Dividing both sides by 0.98s^2:
1m / 0.98s^2 = a

a = 1m / (0.98s^2)

a ≈ 1.02 m/s^2

Now, we can find the tension in the cord using the formula T = W + m * a, where T is the tension, W is the weight, m is the mass, and a is the acceleration.

Plugging in the given values:
T = 61.74 N + 6.3 kg * 1.02 m/s^2

Calculating:
T ≈ 68.838 N

Therefore, the tension in the cord as the elevator accelerates is approximately 68.838 Newtons.

To solve this problem, we need to calculate the tension in the chord.

First, let's find the acceleration of the elevator. We know that the elevator moves 1m in the first 1.4 seconds. To find the acceleration, we can use the following equation:

distance = initial velocity * time + (1/2) * acceleration * time^2

In the given case, the initial velocity is zero as the elevator starts from rest. So the equation simplifies to:

1 = (1/2) * acceleration * (1.4)^2

Simplifying further:

2 = 0.98 * acceleration

acceleration = 2 / 0.98 = 2.04 m/s^2

Now, to find the tension in the chord, we need to consider both the weight of the bundle and the force exerted by the acceleration of the elevator:

Tension in the chord = weight of the bundle + force due to acceleration

Weight of the bundle = mass * acceleration due to gravity

Weight of the bundle = 6.3 kg * 9.8 m/s^2 = 61.74 N

Force due to acceleration = mass * acceleration

Force due to acceleration = 6.3 kg * 2.04 m/s^2 = 12.852 N

Now, we can find the tension in the chord:

Tension in the chord = 61.74 N + 12.852 N = 74.592 N

Therefore, the tension in the chord as the elevator accelerates is approximately 74.592 N.