# Physics-Math

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Suppose that a car starts from rest at position -3.31m and accelerates with a constant acceleration of 4.15m/s^2. At what time t is the velocity of the car 19.2m/s?

• Physics-Math -

v=u+at
19.2=0+4.15t
t=19/4.15
t=4.8

• Physics-Math -

What is the "u" variable standing for?

• Physics-Math -

• Physics-Math -

u is the initial velocity that is 0 as it as rest ..

• Physics-Math -

Thread necro... but I wanted to make sure that anyone seeing this can correctly divide 19.2/4.15 = 4.626506024

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