Write equations for the dissociation of the following in water. Include physical states for all species.
CaCl2
(NH4)2SO4
NaC2H3O2
Your set of questions are all along the same lines. This is not a site where we do the home work for you, so I'll show you one then you have a go at the others.
CaCl2 -> Ca2+ + 2Cl-
To write the equations for the dissociation of the given substances in water, you need to understand the concept of dissociation and the ionic nature of these compounds.
1. CaCl2:
Calcium chloride, CaCl2, dissociates into calcium ions (Ca2+) and chloride ions (Cl-) in water.
The balanced equation for the dissociation of CaCl2 in water is:
CaCl2 (s) ⟶ Ca2+ (aq) + 2Cl- (aq)
(s) denotes solid state, and (aq) denotes aqueous or dissolved in water.
2. (NH4)2SO4:
Ammonium sulfate, (NH4)2SO4, dissociates into ammonium ions (NH4+) and sulfate ions (SO4^2-) in water.
The balanced equation for the dissociation of (NH4)2SO4 in water is:
(NH4)2SO4 (s) ⟶ 2NH4+ (aq) + SO4^2- (aq)
3. NaC2H3O2:
Sodium acetate, NaC2H3O2, dissociates into sodium ions (Na+) and acetate ions (C2H3O2-) in water.
The balanced equation for the dissociation of NaC2H3O2 in water is:
NaC2H3O2 (s) ⟶ Na+ (aq) + C2H3O2- (aq)
Remember, when writing equations for dissociation, the coefficients in front of the ions indicate the number of each ion produced per molecule of the compound that dissociates.