Chemistry

posted by .

A volume of 60.0 of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the KOH solution if 25.2 mL of 1.50M H2SO4 was needed? The equation is 2KOH+H2SO4-->K2SO4+2H2O. I cant seem to get the right answer so please, if you know how to do this explain it fully and work out the problem completely with numbers and equations.

  • Chemistry -

    Has it occurred to you that if you had posted your work I could have found the error in half the time it takes to work the problem.
    H2SO4 + 2KOH ==> K2SO4 + 2H2O

    How many moles H2SO4 were used? That is M x L = moles H2SO4.
    Now convert that to moles KOH. From the equation, it takes 2 moles KOH to equal 1 mole H2SO4; therefore, moles H2SO4 x 1/2 = moles KOH.
    Now M KOH = moles KOH/L KOH.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    How many ml of a 0.827 Molar KOH solution is required for neutralization in a titration of 35.00 ml of 0.737 Molar H2SO4?
  2. Chemistry

    A volume of 70.0mL of aqueous potassium hydroxide(KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the solution if 19.2mL of 1.50M H2SO4 was needed?
  3. Chemistry

    A volume of 50.0 mL of aqueous potassium hydroxide was titrated against a standard solution of sulfuric acid. What was the molarity of the KOH solution if 19.2 mL of 1.50 M H2SO4 was needed?
  4. Chemistry

    A volume of 40.0 of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the solution if 20.2 of 1.50M H2SO4 was needed?
  5. chemistry

    A volume of 40.0 of aqueous potassium hydroxide was titrated against a standard solution of sulfuric acid h2so4. What was the molarity of the solution if 20.02 of 1.50M h2s04 was needed?
  6. pcc

    A volume of 40.0mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the KOH solution if 21.7mL of 1.50 M H2SO4 was needed?
  7. Chemistry

    A volume of 60.0mL of aqueous potassium hydroxide (KOH ) was titrated against a standard solution of sulfuric acid (H 2 SO 4 ). What was the molarity of the KOH solution if 25.7mL of 1.50 M H 2 SO 4 was needed?
  8. Chemistry

    A volume of 80.0mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the KOH solution if 21.7mL of 1.50 M H2SO4 was needed?
  9. chemistry 112

    A volume of 60.0mL of aqueous potassium hydroxide (KOH) was titrated against a standard solution of sulfuric acid (H2SO4). What was the molarity of the KOH solution if 19.2mL of 1.50 M H2SO4 was needed?
  10. Chemistry

    Given the balanced neutralization equation: H2SO4+2KOH→K2SO4+2H2O How many moles of potassium hydroxide (KOH) are required to neutralize 4.5 mol of sulfuric acid (H2SO4)?

More Similar Questions