physics
posted by aimee .
a long jumper travels 8.95 meters during a jump. he moves at 10.8 m/s when starts his leap. at what angle from the horizontal must he have been moving when he started his jump? you may need the double angle formula: 2 sin u cos u sin (2u)

Horizontal distance covered = 8.95 m
= (Vo^2/g)*sin(2u)
Solve for the angle u.
Try deriving the formula. You will learn quite a bit in the process.
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