a friend throws a baseball horizontally. he releases it a height of 2 m and it lands 21 m from his front foot, which is directly below the point at which he released the baseball. (a) how long was it in the air? (b) how fast did he throw it?
(a)
(b)
Show your work for further assistance.
You will not learn much physics by having others do your homework for you.
Start by calculating how long it takes the baseball to fall 2 meters.
i can do the work all on my own but i'm not any good at the formulas, math is a very tough subject for me
Then you need a tutor. Math is the language of Physics. It will do you no good to copy our thinking.
You know, I hate people like this. SHOW THE WORK SO THEY CAN LEARN YOU IDIOT. THEY DIDNT COME HERE TO HEAR YOU INSULT THEM....
To calculate the time the baseball was in the air (a), we can use the horizontal distance it traveled (21 m) and the known acceleration due to gravity (approximately 9.8 m/s^2).
We can use the formula for horizontal distance:
distance = velocity × time
Since the baseball was thrown horizontally, the initial vertical velocity is zero. Therefore, the velocity of the ball is the same as its horizontal velocity.
The horizontal distance (21 m) is equal to the horizontal velocity multiplied by the total time in the air. Therefore, we can rearrange the formula to solve for time:
time = distance / velocity
Substituting the given values, we have:
distance = 21 m
velocity = unknown
To determine the velocity, we can use the vertical motion equation for the time of flight:
distance = initial velocity × time + (1/2) × acceleration × time^2
Since the initial vertical velocity is zero and the motion is only horizontal, this equation simplifies to:
distance = (1/2) × acceleration × time^2
Rearranging the equation, we have:
time = sqrt((2 × distance) / acceleration)
Substituting the known values, we have:
time = sqrt((2 × 21 m) / 9.8 m/s^2)
Simplifying the equation, we get:
time ≈ 1.43 s
Therefore, the baseball was in the air for approximately 1.43 seconds.
To determine the initial horizontal velocity (b), we can use the formula:
velocity = distance / time
Substituting the known values, we have:
distance = 21 m
time = 1.43 s
Calculating the velocity:
velocity = 21 m / 1.43 s ≈ 14.69 m/s
Therefore, the friend threw the baseball with an initial horizontal velocity of approximately 14.69 m/s.