How many grams of NaOH would be needed to react with 199g of HCl?
See your previous post. Same kind of stoichiometry.
To determine the number of grams of NaOH needed to react with 199g of HCl, we need to use the balanced chemical equation for the reaction between NaOH and HCl.
The balanced chemical equation for this reaction is:
NaOH + HCl → NaCl + H2O
From the equation, we can see that the stoichiometric ratio between NaOH and HCl is 1:1. This means that one mole of NaOH reacts with one mole of HCl.
To find the number of moles of HCl in 199g, we need to divide the given mass by the molar mass of HCl (which is 36.46 g/mol).
199g of HCl / 36.46 g/mol = 5.46 moles of HCl
Since the stoichiometric ratio is 1:1, we also need 5.46 moles of NaOH to react with the 5.46 moles of HCl.
To find the number of grams of NaOH, we need to multiply the number of moles of NaOH by its molar mass (which is 39.997 g/mol).
5.46 moles of NaOH * 39.997 g/mol = 218.4 grams of NaOH
Therefore, approximately 218.4 grams of NaOH would be needed to react with 199g of HCl.