physic
posted by noah .
a baseball pitcher throws a baseball with a speed of 4m/s.Estimate the average acceleration of the ball during the throwing motion.In throwing the baseball,the pitcher accelerates the ball through a displacement of about 3.5m,from behind the body to the point where it is released.

4 m/s is a very slow pitch. It is only 8.95 mph. A ball thrown at that speed would not make it to the batter's box without rolling there.
Are you sure you copied the problem correctly? A good pitcher throws fast balls over 90 mph.
Average speed while throwing = 2 m/s.
Time = Distance/(Avg speed) = 3.5m/(2 m/s)
= 1.75 s.
Final speed divided by that time is the acceleration. 
ya
its 41 speed
nvm
thx ya^^ 
Repeat the calculations indicated but starting with V = 41 m/s, not 4 m/s.
The average speed during the throw is
20.5 m/s. The time spent throwing is
T = 3.5/20.5 = 0.1707 s
The acceleration of the ball during the throw is (41 m/s)/(0.1707s)= 240 m/s^2 
How do you find the average speed?

its your first speed divided by 2

Why divide it by two??

Use your arm to throw the ball to the batter
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