How do I solve this problem?
1/b (2b-10) = 17
if the (2b-10) is in the denominator, do this:
multiply both sides by b(2b-10) yielding
1=17b(2b-10)
expand the right side, put it in quadratic form, and use the quadratic equation.
1/b (2b-10) = 17
multiply both sides by b(2b-10) yielding
1=17b(2b-10)
expand the right side, put it in quadratic form, and use the quadratic equation.