a piece of wood that measures 3.0 cm by 4.0 cm by 5.0 cm has a mass of 90.og. what is the density of the wood? would the piece of wood float in water? remember the density of water is 1.00g/ml
To find the density of the wood, we can use the formula:
Density (D) = Mass (m) / Volume (V)
Given that the mass of the wood is 90.0g, we need to calculate the volume first. The volume (V) of a rectangular prism can be calculated by multiplying its length (L), width (W), and height (H):
Volume (V) = Length (L) x Width (W) x Height (H)
In this case, the length (L) is 3.0 cm, the width (W) is 4.0 cm, and the height (H) is 5.0 cm. Plugging in these values, we get:
Volume (V) = 3.0 cm x 4.0 cm x 5.0 cm
Now, let's calculate the volume:
V = 60.0 cm³
Now we have all the values we need to calculate the density:
Density (D) = Mass (m) / Volume (V)
= 90.0 g / 60.0 cm³
Simplifying this:
D = 1.50 g/cm³
So, the density of the wood is 1.50 g/cm³.
To determine whether the piece of wood would float in water, we compare its density to the density of water. Since the density of water is 1.00 g/ml, which is equivalent to 1.00 g/cm³, we can see that the density of the wood (1.50 g/cm³) is greater than the density of water.
According to Archimedes' principle, an object will float in water if its density is less than the density of water. In this case, since the density of the wood is greater than the density of water, the wood will sink and not float in water.