chemistry

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calculate the molality of one molarity solution of sodium nitrare. the density of solution is 1.25g cm cube.

  • chemistry -

    molality = moles/kg solvent
    M = moles/L = 1 mole NaNO3/L soln.

    The mass of 1000 mL =
    1000 x 1.25 g/mL = 1250 grams.
    1 mole NaNO3 = 85 grams (approximately--you need to do it more accurately).
    1250 = mass soln
    85 = mass NaNO3
    ----
    1,165 grams H2O or 1.165 kg solvent.
    m = 1 mole/1.165 kg = 0.858m
    Check my work.

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