Chemistry

posted by .

Hi this is a repost, and I have another 2 questions I posted yesterday. Please help me with these, I need help to verify my work, not confident if I'm doing these right.

Use oxidation numbers to identify if this reaction is REDOX reactions.

3NO2(g) + H2O(l) �� 2HNO3(aq) + NO(g)

3NO2 = -3 for N
= -2 for o2

H2O = +1 for H2
= -2 for O

---->

2HNO3 = +1 for 2H
= -3 for N
= -2 for O3

NO = -3 for N
= -2 for O

Therefore Nitrogen is reduced (one -3 remains on right side)
hence REDOX has occured

Is this right? Also should I be multiplying oxidation numbers if there is a number in front ie. 2SO = -2 oxidation but should I multiply by the 2 infront so is now -4 oxidation for sulphur in 2SO? Please let me know because I haven't done this and if wrong need to correct for a lot of questions :(

• Chemistry -

What you have done confuses me; in a class I could ask a question or two and know how to answer.
The first equation is redox so you are correct; however, not for the reason you cite(-3 N left over on one side versus the other).
The oxidation state for N in NO2 is +4 and not -3. How do you get that? Each O is -2 and there are two of them for a total of -4; therefore, for NO2 to be zero N must be +4. On the right side, each N is +5 in HNO3 and +2 in NO. This is a redox equation because you have something being oxidized and something being reduced (in this case it just happens to be N in NO2---it goes both ways).
As to multiplying by the coefficient, it depends. To identify if redox has occurred, you want to see that EACH atom has changed and I don't multiply by the coefficient to determine that since it isn't needed. In fact, it can be confusing in some situations (such as this one).

So when do I multiply by the coefficient? When I am balancing equations, we want to know the TOTAL charge on side going to a TOTAL charge on the other. In the example you cite for 2SO, here are the two ways of doing it.
#1. Each O is -2, for SO to be zero then S must be +2.

#2. Each O is -2 and that x 2 = -4 for both O atoms. Therefore, both S atoms must be +4 or EACH must be +2. Doing it this way just increases the number or steps (the work) AND the chance of making a mistake.

Similar Questions

1. chemistry

Posted by Bret on Friday, March 16, 2007 at 10:44am. what is the oxidation number for nitrogen in the following?
2. Chemistry

Electron Transfer Theory Write an label the oxidation and reduction half-reaction equations. a) Ni(s) + Cu(NO3)2(aq) -> Cu(s)+ Ni(No3)2(aq) oxidation - Ni(s) -> Ni2+(aq) + 2e- reduction - Cu2+(aq) + 2e- -> Cu(s) b) Pb(s) + …
3. Chemistry

Electron Transfer Theory Write an label the oxidation and reduction half-reaction equations. a) Ni(s) + Cu(NO3)2(aq) -> Cu(s)+ Ni(No3)2(aq) oxidation - Ni(s) -> Ni2+(aq) + 2e- reduction - Cu2+(aq) + 2e- -> Cu(s) b) Pb(s) + …
4. Chemistry

This is for oxidation numbers. I need to know how to show my work. Ex: for NaClO, I have to find the oxidation number for Cl I showed my work. NaClO +1+x+(-2)=0 +1+x-2=0 x-2=-1 x=-1+2 x=+1 Therefore, the oxidation number for chlorine …
5. Chemistry - oxidation numbers

How do you use a Lewis Structure to find the oxidation state of an element. I have this question using the oxidation rule i got +2, however how do i use it with Lewis structure. QUESTION Use the Lewis structure of a thiosulfate ion …
6. Chemistry

Please help me verify the following question: Consider the following ion; XF2-2 What is the oxidation number assigned to element “X”?
7. Chemistry

Please help verify my answer. Not confident it is right: please verify my answer: Consider the following REDOX reaction: Zn(s) + Pb+2(aq) �� Zn+2(aq) + Pb(s) a. Write the oxidation and reduction half-cell reactions. Zn(s) …
8. Chemistry

Please help verify my answer. Not confident it is right: please verify my answer: Consider the following REDOX reaction: Zn(s) + Pb+2(aq) �� Zn+2(aq) + Pb(s) a. Write the oxidation and reduction half-cell reactions. Zn(s) …
9. Chemistry

Use oxidation numbers to identify if this reaction is REDOX reactions. 3NO2(g) + H2O(l) �� 2HNO3(aq) + NO(g) 3NO2 = -3 for N = -2 for o2 H2O = +1 for H2 = -2 for O ----> 2HNO3 = +1 for 2H = -3 for N = -2 for O3 NO …
10. Chemistry URGENT

I need help understanding oxidation I have a problem that states: The proper assignment of oxidation numbers to the elements in the compound LiAsO3 would be: I think the answer is +1 for Li, +3 for As and -2 for O. I think I am confusing …

More Similar Questions

Post a New Question