algebra

posted by Elisa

Use the “difference of squares” rule to factor the following expression: 100a^6-64b^8

  1. Henry

    100a^6 - 64b^8.

    First, take the sqrt of each term:
    (10a^3 + 8b^4)(10a^3 - 8b^4),
    Factor again:

    2(5a^3 + 4b^4)*2(5a^3 - 4b^4).

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