The current I in an electrical conductor varies inversely as the resistance R of the conductor. The current is 2 amperes when the resistance is 940 ohms. What is the current when the resistance is 540 ohms/
I1/I2=R2/R1
I1=2*940/540
To solve this problem, we can use the concept of inverse variation. Inverse variation states that when two quantities, in this case, current and resistance, are inversely proportional, their product remains constant.
Let's denote the current as I and the resistance as R. We can write the inverse variation equation as:
I * R = k
Where "k" is the constant of variation. We can find the value of "k" using the given data:
I = 2 amperes
R = 940 ohms
Substituting these values into the equation:
2 * 940 = k
k = 1880
Now that we have the value of "k," we can use it to find the current when the resistance is 540 ohms.
I * R = k
Substituting the values:
I * 540 = 1880
To isolate I, we divide both sides of the equation by 540:
I = 1880 / 540
I ≈ 3.48 amperes
Therefore, when the resistance is 540 ohms, the current is approximately 3.48 amperes.