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Find the derivative.

11) f(t)=(1)/(sqrt(8t-3))

12) g(t)= ((4t-3)^2)/ ((5t+1)^4)


  • derivative -

    These are standard formulas...

    f()= 1/u
    f'=-u'/u^2 where u is sqrt(8t-3), u'=4/sqrt( )

    g= u/v
    g'=-uv'/v^2 + u'/v where u=(4t-3)^2 v=(5t+1)^4

    I assume you can do it from here.

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