if the concentration of lead in water is 15ppm how much water contains 15 grams of lead?
To find out how much water contains 15 grams of lead when the concentration of lead is 15 ppm (parts per million), we need to use the information given and some unit conversion.
First, let's understand what 15 ppm means. It indicates that there are 15 parts of lead per 1 million parts of water.
Since the concentration of lead is given in parts of lead per million parts of water, we can set up the following equation:
15 ppm = 15 g of lead / X g of water
Now, to solve for X (the amount of water), we can cross multiply and divide:
15 ppm * X g of water = 15 g of lead
X g of water = 15 g of lead / 15 ppm
To perform the calculation, we need to convert ppm to a decimal form. Since 1 ppm is equal to 1 mg/L, we can convert grams to milligrams before carrying out the division.
15 g of lead = 15,000 mg (since 1 g = 1000 mg)
X g of water = 15,000 mg / 15 ppm
To determine the amount of water containing 15 grams of lead when the concentration of lead is 15 ppm, we substitute the values into the equation:
X g of water = 15,000 mg / 15 ppm = 1000 mL / 15 = 66.67 mL
Therefore, 15 grams of lead is present in 66.67 milliliters (mL) of water when the lead concentration is 15 ppm.